(1/2)(6x-8)=41

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Solution for (1/2)(6x-8)=41 equation:



(1/2)(6x-8)=41
We move all terms to the left:
(1/2)(6x-8)-(41)=0
Domain of the equation: 2)(6x-8)!=0
x∈R
We add all the numbers together, and all the variables
(+1/2)(6x-8)-41=0
We multiply parentheses ..
(+6x^2+1/2*-8)-41=0
We multiply all the terms by the denominator
(+6x^2+1-41*2*-8)=0
We get rid of parentheses
6x^2+1-8-41*2*=0
We add all the numbers together, and all the variables
6x^2=0
a = 6; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·6·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{12}=0$

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