(1/2)(8x+16)=(1/3)(24x-12)

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Solution for (1/2)(8x+16)=(1/3)(24x-12) equation: 



(1/2)(8x+16)=(1/3)(24x-12)

We move all terms to the left:

(1/2)(8x+16)-((1/3)(24x-12))=0



Domain of the equation: 2)(8x+16)!=0

x∈R





Domain of the equation: 3)(24x-12))!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)(8x+16)-((+1/3)(24x-12))=0

We multiply parentheses ..

(+8x^2+1/2*16)-((+1/3)(24x-12))=0

We calculate fractions


((+8x^2+1*3)(24x-12)))/96x^2+()/96x^2=0

We can not solve this equation

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