(1/2)(8x-14)=-13

Solution for (1/2)(8x-14)=-13 equation:

(1/2)(8x-14)=-13

We move all terms to the left:

(1/2)(8x-14)-(-13)=0


Domain of the equation: 2)(8x-14)!=0

x∈R


We add all the numbers together, and all the variables

(+1/2)(8x-14)-(-13)=0

We add all the numbers together, and all the variables

(+1/2)(8x-14)+13=0

We multiply parentheses ..

(+8x^2+1/2*-14)+13=0

We multiply all the terms by the denominator


(+8x^2+1+13*2*-14)=0

We get rid of parentheses

8x^2+1-14+13*2*=0

We add all the numbers together, and all the variables

8x^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{16}=0$