(1/2)(c-16)=4

Solution for (1/2)(c-16)=4 equation:

(1/2)(c-16)=4

We move all terms to the left:

(1/2)(c-16)-(4)=0


Domain of the equation: 2)(c-16)!=0

c∈R


We add all the numbers together, and all the variables

(+1/2)(c-16)-4=0

We multiply parentheses ..

(+c^2+1/2*-16)-4=0

We multiply all the terms by the denominator


(+c^2+1-4*2*-16)=0

We get rid of parentheses

c^2+1-16-4*2*=0

We add all the numbers together, and all the variables

c^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{0}{2}=0$