(1/2)(x)+(1/2)(x)=x+1

Solution for (1/2)(x)+(1/2)(x)=x+1 equation:

(1/2)(x)+(1/2)(x)=x+1

We move all terms to the left:

(1/2)(x)+(1/2)(x)-(x+1)=0


Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/2)x+(+1/2)x-(x+1)=0

We multiply parentheses

x^2+x^2-(x+1)=0

We get rid of parentheses

x^2+x^2-x-1=0

We add all the numbers together, and all the variables

2x^2-1x-1=0

a = 2; b = -1; c = -1;
Δ = b2-4ac
Δ = -12-4·2·(-1)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-3}{2*2}=\frac{-2}{4}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+3}{2*2}=\frac{4}{4}
=1
$