(1/2)(x+8)+(3/2)(x)=10

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Solution for (1/2)(x+8)+(3/2)(x)=10 equation: 



(1/2)(x+8)+(3/2)(x)=10

We move all terms to the left:

(1/2)(x+8)+(3/2)(x)-(10)=0



Domain of the equation: 2)(x+8)!=0

x∈R





Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)(x+8)+(+3/2)x-10=0

We multiply parentheses

3x^2+(+1/2)(x+8)-10=0

We multiply parentheses ..

3x^2+(+x^2+1/2*8)-10=0

We multiply all the terms by the denominator


x^2+3x^2*2*8)+(+1-10*2*8)=0

We add all the numbers together, and all the variables

x^2+3x^2*2*8)+(-159)=0

We add all the numbers together, and all the variables

x^2+3x^2*2*8)+(=0

Wy multiply elements

x^2+48x^3*8=0

We do not support expression: x^3

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