(1/2)(x-120)=15+8x

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Solution for (1/2)(x-120)=15+8x equation: 



(1/2)(x-120)=15+8x

We move all terms to the left:

(1/2)(x-120)-(15+8x)=0



Domain of the equation: 2)(x-120)!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)(x-120)-(8x+15)=0

We get rid of parentheses

(+1/2)(x-120)-8x-15=0

We multiply parentheses ..

(+x^2+1/2*-120)-8x-15=0

We multiply all the terms by the denominator


(+x^2+1-8x*2*-120)-15*2*-120)=0

We add all the numbers together, and all the variables

(+x^2+1-8x*2*-120)=0

We get rid of parentheses

x^2-8x*2*+1-120=0

We add all the numbers together, and all the variables

x^2-8x*2*-119=0

Wy multiply elements

x^2-16x^2-119=0

We add all the numbers together, and all the variables

-15x^2-119=0

a = -15; b = 0; c = -119;
Δ = b2-4ac
Δ = 02-4·(-15)·(-119)
Δ = -7140
Delta is less than zero, so there is no solution for the equation

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