(1/2)(y-36)=-12

Solution for (1/2)(y-36)=-12 equation:

(1/2)(y-36)=-12

We move all terms to the left:

(1/2)(y-36)-(-12)=0


Domain of the equation: 2)(y-36)!=0

y∈R


We add all the numbers together, and all the variables

(+1/2)(y-36)-(-12)=0

We add all the numbers together, and all the variables

(+1/2)(y-36)+12=0

We multiply parentheses ..

(+y^2+1/2*-36)+12=0

We multiply all the terms by the denominator


(+y^2+1+12*2*-36)=0

We get rid of parentheses

y^2+1-36+12*2*=0

We add all the numbers together, and all the variables

y^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{2}=0$