(1/2)*(x-4)=1/3x+2

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Solution for (1/2)*(x-4)=1/3x+2 equation:



(1/2)(x-4)=1/3x+2
We move all terms to the left:
(1/2)(x-4)-(1/3x+2)=0
Domain of the equation: 2)(x-4)!=0
x∈R
Domain of the equation: 3x+2)!=0
x∈R
We add all the numbers together, and all the variables
(+1/2)(x-4)-(1/3x+2)=0
We get rid of parentheses
(+1/2)(x-4)-1/3x-2=0
We multiply parentheses ..
(+x^2+1/2*-4)-1/3x-2=0
We calculate fractions
((+x^2+1*3x)/(-4)*3x+2*)+()/(-4)*3x-2+2*)=0
We calculate terms in parentheses: +((+x^2+1*3x)/(-4)*3x+2*), so:
(+x^2+1*3x)/(-4)*3x+2*
We add all the numbers together, and all the variables
(+x^2+1*3x)/(-4)*3x
We multiply all the terms by the denominator
(+x^2+1*3x)
We get rid of parentheses
x^2+1*3x
Wy multiply elements
x^2+3x
Back to the equation:
+(x^2+3x)
We add all the numbers together, and all the variables
(x^2+3x)+()/(-4)*3x=0
We get rid of parentheses
x^2+3x+()/(-4)*3x=0
We multiply all the terms by the denominator
x^2*(-4)*3x+3x*(-4)*3x+()=0
We add all the numbers together, and all the variables
x^2*(-4)*3x+3x*(-4)*3x=0
We multiply parentheses
x^2*(-4)*3x-36x^2=0
We add all the numbers together, and all the variables
-36x^2+x^2*(-4)*3x=0

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