(1/2)+(1/d-2)=(d/16)

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Solution for (1/2)+(1/d-2)=(d/16) equation:


D( d )

d = 0

d = 0

d = 0

d in (-oo:0) U (0:+oo)

1/d+1/2-2 = d/16 // - d/16

1/d-(d/16)+1/2-2 = 0

1*d^-1-1/16*d^1-3/2*d^0 = 0

(1*d^0-1/16*d^2-3/2*d^1)/(d^1) = 0 // * d^2

d^1*(1*d^0-1/16*d^2-3/2*d^1) = 0

d^1

(-1/16)*d^2+(-3/2)*d+1 = 0

(-1/16)*d^2+(-3/2)*d+1 = 0

DELTA = (-3/2)^2-(1*4*(-1/16))

DELTA = 5/2

DELTA > 0

d = ((5/2)^(1/2)-(-3/2))/(2*(-1/16)) or d = (-(-3/2)-(5/2)^(1/2))/(2*(-1/16))

d = -8*((5/2)^(1/2)+3/2) or d = -8*(3/2-(5/2)^(1/2))

d in { -8*((5/2)^(1/2)+3/2), -8*(3/2-(5/2)^(1/2))}

d in { -8*((5/2)^(1/2)+3/2), -8*(3/2-(5/2)^(1/2)) }

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