(1/2)+(1/x-2)=(x/16)

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Solution for (1/2)+(1/x-2)=(x/16) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+1/2-2 = x/16 // - x/16

1/x-(x/16)+1/2-2 = 0

1*x^-1-1/16*x^1-3/2*x^0 = 0

(1*x^0-1/16*x^2-3/2*x^1)/(x^1) = 0 // * x^2

x^1*(1*x^0-1/16*x^2-3/2*x^1) = 0

x^1

(-1/16)*x^2+(-3/2)*x+1 = 0

(-1/16)*x^2+(-3/2)*x+1 = 0

DELTA = (-3/2)^2-(1*4*(-1/16))

DELTA = 5/2

DELTA > 0

x = ((5/2)^(1/2)-(-3/2))/(2*(-1/16)) or x = (-(-3/2)-(5/2)^(1/2))/(2*(-1/16))

x = -8*((5/2)^(1/2)+3/2) or x = -8*(3/2-(5/2)^(1/2))

x in { -8*((5/2)^(1/2)+3/2), -8*(3/2-(5/2)^(1/2))}

x in { -8*((5/2)^(1/2)+3/2), -8*(3/2-(5/2)^(1/2)) }

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