(1/2)+x+4=(2/3)x+1

Solution for (1/2)+x+4=(2/3)x+1 equation:

(1/2)+x+4=(2/3)x+1

We move all terms to the left:

(1/2)+x+4-((2/3)x+1)=0


Domain of the equation: 3)x+1)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

x-((+2/3)x+1)+4+(+1/2)=0

We get rid of parentheses

x-((+2/3)x+1)+4+1/2=0

We calculate fractions


x+()/3x+1)*2)+3x/3x+1)*2)+4=0

We calculate fractions


x+(()*3x)/9x^2+1*2)+3x*3x)/9x^2=0

We multiply all the terms by the denominator


x*9x^2+(()*3x)+1*2)+3x*3x)=0


We calculate terms in parentheses: +(()*3x), so:

()*3x


Wy multiply elements

9x^3+6x^2+(()*3x)=0


We calculate terms in parentheses: +(()*3x), so:

()*3x


We do not support expression: x^3