(1/2)-(1/x)=1/3x

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Solution for (1/2)-(1/x)=1/3x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/2-(1/x) = (1/3)*x // - (1/3)*x

1/2-((1/3)*x)-(1/x) = 0

(-1/3)*x-x^-1+1/2 = 0

1/2*x^0-1/3*x^1-1*x^-1 = 0

(1/2*x^1-1/3*x^2-1*x^0)/(x^1) = 0 // * x^2

x^1*(1/2*x^1-1/3*x^2-1*x^0) = 0

x^1

(-1/3)*x^2+(1/2)*x-1 = 0

(-1/3)*x^2+(1/2)*x-1 = 0

DELTA = (1/2)^2-(-1*4*(-1/3))

DELTA = -13/12

DELTA < 0

x in { } 

x belongs to the empty set

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