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(1/2)3x+8=2x+24
We move all terms to the left:
(1/2)3x+8-(2x+24)=0
Domain of the equation: 2)3x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/2)3x-(2x+24)+8=0
We multiply parentheses
3x^2-(2x+24)+8=0
We get rid of parentheses
3x^2-2x-24+8=0
We add all the numbers together, and all the variables
3x^2-2x-16=0
a = 3; b = -2; c = -16;
Δ = b2-4ac
Δ = -22-4·3·(-16)
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-14}{2*3}=\frac{-12}{6} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+14}{2*3}=\frac{16}{6} =2+2/3 $
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