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(1/2)5x+8=3x+12
We move all terms to the left:
(1/2)5x+8-(3x+12)=0
Domain of the equation: 2)5x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+1/2)5x-(3x+12)+8=0
We multiply parentheses
5x^2-(3x+12)+8=0
We get rid of parentheses
5x^2-3x-12+8=0
We add all the numbers together, and all the variables
5x^2-3x-4=0
a = 5; b = -3; c = -4;
Δ = b2-4ac
Δ = -32-4·5·(-4)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{89}}{2*5}=\frac{3-\sqrt{89}}{10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{89}}{2*5}=\frac{3+\sqrt{89}}{10} $
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