(1/2)b+(4/5)=b-(3/10)

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Solution for (1/2)b+(4/5)=b-(3/10) equation: 



(1/2)b+(4/5)=b-(3/10)

We move all terms to the left:

(1/2)b+(4/5)-(b-(3/10))=0



Domain of the equation: 2)b!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

(+1/2)b-(b-(+3/10))+(+4/5)=0

We multiply parentheses

b^2-(b-(+3/10))+(+4/5)=0

We get rid of parentheses

b^2-(b-(+3/10))+4/5=0

We calculate fractions


b^2+(-(b-(+3*5)/()+()/()=0



We calculate terms in parentheses: +(-(b-(+3*5)/()+()/(), so:

-(b-(+3*5)/()+()/(

We can not solve this equation

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