(1/2)b+4=(1/8)+88

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Solution for (1/2)b+4=(1/8)+88 equation: 



(1/2)b+4=(1/8)+88

We move all terms to the left:

(1/2)b+4-((1/8)+88)=0



Domain of the equation: 2)b!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

(+1/2)b+4-((+1/8)+88)=0

We multiply parentheses

b^2+4-((+1/8)+88)=0

We multiply all the terms by the denominator


b^2*8)+88)+4*8)+88)-((+1=0

Wy multiply elements

64b^4=0

We do not support ebpression: b^4

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