(1/2)l+(2/4)=(2/3)l+5

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Solution for (1/2)l+(2/4)=(2/3)l+5 equation: 



(1/2)l+(2/4)=(2/3)l+5

We move all terms to the left:

(1/2)l+(2/4)-((2/3)l+5)=0



Domain of the equation: 2)l!=0

l!=0/1

l!=0

l∈R





Domain of the equation: 3)l+5)!=0

l!=0/1

l!=0

l∈R



We add all the numbers together, and all the variables

(+1/2)l-((+2/3)l+5)+(+2/4)=0

We multiply parentheses

l^2-((+2/3)l+5)+(+2/4)=0

We get rid of parentheses

l^2-((+2/3)l+5)+2/4=0

We calculate fractions


l^2+()/3l+5)*4)+6l/3l+5)*4)=0

We calculate fractions


l^2+(()*3l)/9l^2+5*4)+6l*3l)/9l^2=0

We multiply all the terms by the denominator


l^2*9l^2+(()*3l)+5*4)+6l*3l)=0



We calculate terms in parentheses: +(()*3l), so:

()*3l



Wy multiply elements

9l^4+60l^2+(()*3l)=0



We calculate terms in parentheses: +(()*3l), so:

()*3l



We do not support elpression: l^4

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