(1/2)n-(3/14)=(1/28)

Solution for (1/2)n-(3/14)=(1/28) equation:

(1/2)n-(3/14)=(1/28)

We move all terms to the left:

(1/2)n-(3/14)-((1/28))=0


Domain of the equation: 2)n!=0

n!=0/1

n!=0

n∈R


We add all the numbers together, and all the variables

(+1/2)n-(+3/14)-((+1/28))=0

We multiply parentheses

n^2-(+3/14)-((+1/28))=0

We get rid of parentheses

n^2-3/14-((+1/28))=0

We calculate fractions


n^2+()/()+()/()=0

We add all the numbers together, and all the variables

n^2+2=0

a = 1; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·1·2
Δ = -8
Delta is less than zero, so there is no solution for the equation