(1/2)p+p+2p-10=130

Solution for (1/2)p+p+2p-10=130 equation:

(1/2)p+p+2p-10=130

We move all terms to the left:

(1/2)p+p+2p-10-(130)=0


Domain of the equation: 2)p!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

(+1/2)p+p+2p-10-130=0

We add all the numbers together, and all the variables

3p+(+1/2)p-140=0

We multiply parentheses

p^2+3p-140=0

a = 1; b = 3; c = -140;
Δ = b2-4ac
Δ = 32-4·1·(-140)
Δ = 569
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{569}}{2*1}=\frac{-3-\sqrt{569}}{2}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{569}}{2*1}=\frac{-3+\sqrt{569}}{2}
$