(1/2)x+(2/4)=(2/3)x+5

Solution for (1/2)x+(2/4)=(2/3)x+5 equation:

(1/2)x+(2/4)=(2/3)x+5

We move all terms to the left:

(1/2)x+(2/4)-((2/3)x+5)=0


Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 3)x+5)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/2)x-((+2/3)x+5)+(+2/4)=0

We multiply parentheses

x^2-((+2/3)x+5)+(+2/4)=0

We get rid of parentheses

x^2-((+2/3)x+5)+2/4=0

We calculate fractions


x^2+()/3x+5)*4)+6x/3x+5)*4)=0

We calculate fractions


x^2+(()*3x)/9x^2+5*4)+6x*3x)/9x^2=0

We multiply all the terms by the denominator


x^2*9x^2+(()*3x)+5*4)+6x*3x)=0


We calculate terms in parentheses: +(()*3x), so:

()*3x


Wy multiply elements

9x^4+60x^2+(()*3x)=0


We calculate terms in parentheses: +(()*3x), so:

()*3x


We do not support expression: x^4