(1/2)x+(3/2)=(7/2)

Solution for (1/2)x+(3/2)=(7/2) equation:

(1/2)x+(3/2)=(7/2)

We move all terms to the left:

(1/2)x+(3/2)-((7/2))=0


Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/2)x+(+3/2)-((+7/2))=0

We multiply parentheses

x^2+(+3/2)-((+7/2))=0

We get rid of parentheses

x^2+3/2-((+7/2))=0

We calculate fractions


x^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2}=0$