(1/2)x+(3/4)-2x=2(1/4)-5x+16

Solution for (1/2)x+(3/4)-2x=2(1/4)-5x+16 equation:

(1/2)x+(3/4)-2x=2(1/4)-5x+16

We move all terms to the left:

(1/2)x+(3/4)-2x-(2(1/4)-5x+16)=0


Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 4)-5x+16)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/2)x-2x-(2(+1/4)-5x+16)+(+3/4)=0

We add all the numbers together, and all the variables

-2x+(+1/2)x-(2(+1/4)-5x+16)+(+3/4)=0

We multiply parentheses

x^2-2x-(2(+1/4)-5x+16)+(+3/4)=0

We get rid of parentheses

x^2-2x-(2(+1/4)-5x+16)+3/4=0

We calculate fractions


x^2-2x=0

a = 1; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·1·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*1}=\frac{0}{2}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*1}=\frac{4}{2}
=2
$