(1/2)x+(3/4)=1

Solution for (1/2)x+(3/4)=1 equation:

(1/2)x+(3/4)=1

We move all terms to the left:

(1/2)x+(3/4)-(1)=0


Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R


determiningTheFunctionDomain
(1/2)x-1+(3/4)=0

We add all the numbers together, and all the variables

(+1/2)x-1+(+3/4)=0

We multiply parentheses

x^2-1+(+3/4)=0

We get rid of parentheses

x^2-1+3/4=0

We multiply all the terms by the denominator


x^2*4+3-1*4=0

We add all the numbers together, and all the variables

x^2*4-1=0

Wy multiply elements

4x^2-1=0

a = 4; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·4·(-1)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4}{2*4}=\frac{-4}{8}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4}{2*4}=\frac{4}{8}
=1/2
$