(1/2)x+1/5=4((4/5x)+5)

Solution for (1/2)x+1/5=4((4/5x)+5) equation:

(1/2)x+1/5=4((4/5x)+5)

We move all terms to the left:

(1/2)x+1/5-(4((4/5x)+5))=0


Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 5x)+5))!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/2)x-(4((+4/5x)+5))+1/5=0

We multiply parentheses

x^2-(4((+4/5x)+5))+1/5=0

We calculate fractions


x^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2}=0$