(1/2)x+35=635

Solution for (1/2)x+35=635 equation:

(1/2)x+35=635

We move all terms to the left:

(1/2)x+35-(635)=0


Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/2)x+35-635=0

We add all the numbers together, and all the variables

(+1/2)x-600=0

We multiply parentheses

x^2-600=0

a = 1; b = 0; c = -600;
Δ = b2-4ac
Δ = 02-4·1·(-600)
Δ = 2400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2400}=\sqrt{400*6}=\sqrt{400}*\sqrt{6}=20\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{6}}{2*1}=\frac{0-20\sqrt{6}}{2}
=-\frac{20\sqrt{6}}{2}
=-10\sqrt{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{6}}{2*1}=\frac{0+20\sqrt{6}}{2}
=\frac{20\sqrt{6}}{2}
=10\sqrt{6}
$