(1/2)x-3+(1/3)(x+5)=-1

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Solution for (1/2)x-3+(1/3)(x+5)=-1 equation: 



(1/2)x-3+(1/3)(x+5)=-1

We move all terms to the left:

(1/2)x-3+(1/3)(x+5)-(-1)=0



Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3)(x+5)!=0

x∈R



We add all the numbers together, and all the variables

(+1/2)x+(+1/3)(x+5)-3-(-1)=0

We add all the numbers together, and all the variables

(+1/2)x+(+1/3)(x+5)-2=0

We multiply parentheses

x^2+(+1/3)(x+5)-2=0

We multiply parentheses ..

x^2+(+x^2+1/3*5)-2=0

We multiply all the terms by the denominator


x^2+x^2*3*5)+(+1-2*3*5)=0

We add all the numbers together, and all the variables

x^2+x^2*3*5)+(-29)=0

We add all the numbers together, and all the variables

x^2+x^2*3*5)+(=0

Wy multiply elements

x^2+15x^3*5=0

We do not support expression: x^3

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