(1/2)x-3=(1/5)x+6

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Solution for (1/2)x-3=(1/5)x+6 equation:



(1/2)x-3=(1/5)x+6
We move all terms to the left:
(1/2)x-3-((1/5)x+6)=0
Domain of the equation: 2)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 5)x+6)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+1/2)x-((+1/5)x+6)-3=0
We multiply parentheses
x^2-((+1/5)x+6)-3=0
We multiply all the terms by the denominator
x^2*5)x+6)-((-3*5)x+6)+1=0
We add all the numbers together, and all the variables
x^2*5)x+6)-((-15)x+6)+1=0
Wy multiply elements
5x^3-15)x+6)+1=0
We do not support expression: x^3

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