(1/2)y+3.2y=20

Solution for (1/2)y+3.2y=20 equation:

(1/2)y+3.2y=20

We move all terms to the left:

(1/2)y+3.2y-(20)=0


Domain of the equation: 2)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+1/2)y+3.2y-20=0

We add all the numbers together, and all the variables

3.2y+(+1/2)y-20=0

We multiply parentheses

y^2+3.2y-20=0

a = 1; b = 3.2; c = -20;
Δ = b2-4ac
Δ = 3.22-4·1·(-20)
Δ = 90.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3.2)-\sqrt{90.24}}{2*1}=\frac{-3.2-\sqrt{90.24}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3.2)+\sqrt{90.24}}{2*1}=\frac{-3.2+\sqrt{90.24}}{2}
$