(1/20)+(1/30)=(1/t)

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Solution for (1/20)+(1/30)=(1/t) equation: 


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

1/20+1/30 = 1/t // - 1/t

1/20-(1/t)+1/30 = 0

1/20-t^-1+1/30 = 0

-1*t^-1 = -1/12 // : -1

t^-1 = 1/12

-1 < 0

1/(t^1) = 1/12 // * t^1

1 = 1/12*t^1 // : 1/12

12 = t^1

t = 12

t = 12

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