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(1/2q+1)=-3(2q+1)+4(2q+1)
We move all terms to the left:
(1/2q+1)-(-3(2q+1)+4(2q+1))=0
Domain of the equation: 2q+1)!=0We get rid of parentheses
q∈R
1/2q-(-3(2q+1)+4(2q+1))+1=0
We multiply all the terms by the denominator
-((-3(2q+1)+4(2q+1)))*2q+1*2q+1=0
Wy multiply elements
-((-3(2q+1)+4(2q+1)))*2q+2q+1=0
We add all the numbers together, and all the variables
2q-((-3(2q+1)+4(2q+1)))*2q+1=0
We move all terms containing q to the left, all other terms to the right
2q-((-3(2q+1)+4(2q+1)))*2q=-1
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