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(1/2x)(x+1)=210
We move all terms to the left:
(1/2x)(x+1)-(210)=0
Domain of the equation: 2x)(x+1)!=0We add all the numbers together, and all the variables
x∈R
(+1/2x)(x+1)-210=0
We multiply parentheses ..
(+x^2+x)-210=0
We get rid of parentheses
x^2+x-210=0
a = 1; b = 1; c = -210;
Δ = b2-4ac
Δ = 12-4·1·(-210)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-29}{2*1}=\frac{-30}{2} =-15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+29}{2*1}=\frac{28}{2} =14 $
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