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(1/2x)+(3/2)(x+1)-1/4=5
We move all terms to the left:
(1/2x)+(3/2)(x+1)-1/4-(5)=0
Domain of the equation: 2x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 2)(x+1)!=0determiningTheFunctionDomain (1/2x)+(3/2)(x+1)-5-1/4=0
x∈R
We add all the numbers together, and all the variables
(+1/2x)+(+3/2)(x+1)-5-1/4=0
We get rid of parentheses
1/2x+(+3/2)(x+1)-5-1/4=0
We multiply parentheses ..
(+3x^2+3/2*1)+1/2x-5-1/4=0
We calculate fractions
((+3x^2+3*2x*4)/16x^2+()/16x^2+(-4x^2)/16x^2-5=0
We can not solve this equation
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