(1/2x)-7=1/3(x-12)

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Solution for (1/2x)-7=1/3(x-12) equation: 



(1/2x)-7=1/3(x-12)

We move all terms to the left:

(1/2x)-7-(1/3(x-12))=0



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 3(x-12))!=0

x∈R



We add all the numbers together, and all the variables

(+1/2x)-(1/3(x-12))-7=0

We get rid of parentheses

1/2x-(1/3(x-12))-7=0

We calculate fractions


(3xx/(6x^2x+(-(1*2x)/(6x^2x-7=0

We can not solve this equation

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