(1/2x+42)+(1/4x-10)=x-623

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Solution for (1/2x+42)+(1/4x-10)=x-623 equation: 



(1/2x+42)+(1/4x-10)=x-623

We move all terms to the left:

(1/2x+42)+(1/4x-10)-(x-623)=0



Domain of the equation: 2x+42)!=0

x∈R





Domain of the equation: 4x-10)!=0

x∈R



We get rid of parentheses

1/2x+1/4x-x+42-10+623=0

We calculate fractions


-x+4x/8x^2+2x/8x^2+42-10+623=0

We add all the numbers together, and all the variables

-1x+4x/8x^2+2x/8x^2+655=0

We multiply all the terms by the denominator


-1x*8x^2+4x+2x+655*8x^2=0

We add all the numbers together, and all the variables

6x-1x*8x^2+655*8x^2=0

Wy multiply elements

-8x^3+5240x^2+6x=0

We do not support expression: x^3

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