(1/3)(-6y+27)=-5+12y

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Solution for (1/3)(-6y+27)=-5+12y equation: 


y in (-oo:+oo)

(1/3)*(27-6*y) = 12*y-5 // - 12*y-5

(1/3)*(27-6*y)-(12*y)+5 = 0

(1/3)*(27-6*y)-12*y+5 = 0

1/3*(27-6*y)-12*y+5 = 0

1/3*(27-6*y)-12*y+5 = 0

5-14*y+9 = 0

14-14*y = 0

14-14*y = 0

14-14*y = 0 // - 14

-14*y = -14 // : -14

y = -14/(-14)

y = 1

y = 1

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