(1/3)(12x+21)=(1/5)(20x+70)

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Solution for (1/3)(12x+21)=(1/5)(20x+70) equation: 



(1/3)(12x+21)=(1/5)(20x+70)

We move all terms to the left:

(1/3)(12x+21)-((1/5)(20x+70))=0



Domain of the equation: 3)(12x+21)!=0

x∈R





Domain of the equation: 5)(20x+70))!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)(12x+21)-((+1/5)(20x+70))=0

We multiply parentheses ..

(+12x^2+1/3*21)-((+1/5)(20x+70))=0

We calculate fractions


((+12x^2+1*5)(20x+70)))/315x^2+()/315x^2=0

We can not solve this equation

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