(1/3)(12x-16)=(2/5)(12-3x)

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Solution for (1/3)(12x-16)=(2/5)(12-3x) equation: 



(1/3)(12x-16)=(2/5)(12-3x)

We move all terms to the left:

(1/3)(12x-16)-((2/5)(12-3x))=0



Domain of the equation: 3)(12x-16)!=0

x∈R





Domain of the equation: 5)(12-3x))!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)(12x-16)-((+2/5)(-3x+12))=0

We multiply parentheses ..

(+12x^2+1/3*-16)-((+2/5)(-3x+12))=0

We calculate fractions


((+12x^2+1*5)(-3x+12)))/(-16)*5)(-3x+12))+3*)+()/(-16)*5)(-3x+12))+3*)=0

We calculate fractions


(((+12x^2+1*5)(-3x+12)))*(-16)*5)(-3x+12))+3*))/(-3x)+(-16)*5)(-3x+12))+3*)+()*()/(-3x)=0

We can not solve this equation

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