(1/3)(12x-3)=7

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Solution for (1/3)(12x-3)=7 equation: 



(1/3)(12x-3)=7

We move all terms to the left:

(1/3)(12x-3)-(7)=0



Domain of the equation: 3)(12x-3)!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)(12x-3)-7=0

We multiply parentheses ..

(+12x^2+1/3*-3)-7=0

We multiply all the terms by the denominator


(+12x^2+1-7*3*-3)=0

We get rid of parentheses

12x^2+1-3-7*3*=0

We add all the numbers together, and all the variables

12x^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$

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