(1/3)(2b+9)=(2/3)(b=9/2)

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Solution for (1/3)(2b+9)=(2/3)(b=9/2) equation: 



(1/3)(2b+9)=(2/3)(b=9/2)

We move all terms to the left:

(1/3)(2b+9)-((2/3)(b)=0



Domain of the equation: 3)(2b+9)!=0

b∈R





Domain of the equation: 3)b!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

(+1/3)(2b+9)-((+2/3)b=0

We multiply parentheses ..

(+2b^2+1/3*9)-((+2/3)b=0

We calculate fractions

We do not support ebpression: b^3

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