(1/3)(2x-3)(3x+4)=0

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Solution for (1/3)(2x-3)(3x+4)=0 equation: 


x in (-oo:+oo)

(1/3)*(2*x-3)*(3*x+4) = 0

1/3*(2*x-3)*(3*x+4) = 0

( 2*x-3 )

2*x-3 = 0 // + 3

2*x = 3 // : 2

x = 3/2

( 3*x+4 )

3*x+4 = 0 // - 4

3*x = -4 // : 3

x = -4/3

x in { 3/2, -4/3 }

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