(1/3)(2x-4)+5=(-2/3)(x+1

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Solution for (1/3)(2x-4)+5=(-2/3)(x+1 equation:



(1/3)(2x-4)+5=(-2/3)(x+1
We move all terms to the left:
(1/3)(2x-4)+5-((-2/3)(x+1)=0
Domain of the equation: 3)(2x-4)!=0
x∈R
Domain of the equation: 3)(x+1)+5!=0
x∈R
We add all the numbers together, and all the variables
(+1/3)(2x-4)-((-2/3)(x+1)+5=0
We multiply parentheses ..
(+2x^2+1/3*-4)-((-2/3)(x+1)+5=0
We calculate fractions
((+2x^2+1*3)(x+1)+5)/(-4)*3)(x+1)+5+3*)+()/(-4)*3)(x+1)+5+3*)=0
We calculate fractions
(((+2x^2+1*3)(x+1)+5)*(-4)*3)x/((-4)*3)(x*(-4)*3)x-4)*3)x/((-4)*3)(x*(-4)*3)x+5+1+3*)+()*(=0
We calculate fractions
-4)*3)x+5+1+3*)+()*(+((((+2x^2+1*3)(x+1)+5)*(-4)*3)x*(()/(((-4)*3)(x*(-4)*3)x*(()+(-4)*3)x*((-4)*3)(x*(-4)*3)x)/(((-4)*3)(x*(-4)*3)x*(()-4)*3)(x*(=0
We can not solve this equation

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