(1/3)(90x-12)=(1/2)(8x+10)

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Solution for (1/3)(90x-12)=(1/2)(8x+10) equation: 



(1/3)(90x-12)=(1/2)(8x+10)

We move all terms to the left:

(1/3)(90x-12)-((1/2)(8x+10))=0



Domain of the equation: 3)(90x-12)!=0

x∈R





Domain of the equation: 2)(8x+10))!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)(90x-12)-((+1/2)(8x+10))=0

We multiply parentheses ..

(+90x^2+1/3*-12)-((+1/2)(8x+10))=0

We calculate fractions


((+90x^2+1*2)(8x+10)))/(-12)*2)(8x+10))+3*)+()/(-12)*2)(8x+10))+3*)=0

We calculate fractions


(((+90x^2+1*2)(8x+10)))*(-12)*2)(8x+10))+3*))/((*(-12)*2)8x)+(-12)*2)(8x+10))+3*)+()*()/((*(-12)*2)8x)=0

We can not solve this equation

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