(1/3)(9c-36)=-9

Solution for (1/3)(9c-36)=-9 equation:

(1/3)(9c-36)=-9

We move all terms to the left:

(1/3)(9c-36)-(-9)=0


Domain of the equation: 3)(9c-36)!=0

c∈R


We add all the numbers together, and all the variables

(+1/3)(9c-36)-(-9)=0

We add all the numbers together, and all the variables

(+1/3)(9c-36)+9=0

We multiply parentheses ..

(+9c^2+1/3*-36)+9=0

We multiply all the terms by the denominator


(+9c^2+1+9*3*-36)=0

We get rid of parentheses

9c^2+1-36+9*3*=0

We add all the numbers together, and all the variables

9c^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{0}{18}=0$