(1/3)(9x+11)=4x+(1/2)

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Solution for (1/3)(9x+11)=4x+(1/2) equation:



(1/3)(9x+11)=4x+(1/2)
We move all terms to the left:
(1/3)(9x+11)-(4x+(1/2))=0
Domain of the equation: 3)(9x+11)!=0
x∈R
We add all the numbers together, and all the variables
(+1/3)(9x+11)-(4x+(+1/2))=0
We multiply parentheses ..
(+9x^2+1/3*11)-(4x+(+1/2))=0
We calculate fractions
9x^2/()+(-(4x+33)/()=0
We calculate terms in parentheses: +(-(4x+33)/(), so:
-(4x+33)/(
We multiply all the terms by the denominator
-(4x+33)
We get rid of parentheses
-4x-33
Back to the equation:
+(-4x-33)
We get rid of parentheses
9x^2/()-4x-33=0
We multiply all the terms by the denominator
9x^2-4x*()-33*()=0
We add all the numbers together, and all the variables
9x^2-4x*()=0

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