(1/3)(9x+3)=3x+1

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Solution for (1/3)(9x+3)=3x+1 equation: 


x in (-oo:+oo)

(1/3)*(9*x+3) = 3*x+1 // - 3*x+1

(1/3)*(9*x+3)-(3*x)-1 = 0

(1/3)*(9*x+3)-3*x-1 = 0

1/3*(9*x+3)-3*x-1 = 0

1/3*(9*x+3)-3*x-1 = 0

1-1 = 0

0 = 0

0 = 0

x belongs to the empty set

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