(1/3)(9x-45)=27

Solution for (1/3)(9x-45)=27 equation:

(1/3)(9x-45)=27

We move all terms to the left:

(1/3)(9x-45)-(27)=0


Domain of the equation: 3)(9x-45)!=0

x∈R


We add all the numbers together, and all the variables

(+1/3)(9x-45)-27=0

We multiply parentheses ..

(+9x^2+1/3*-45)-27=0

We multiply all the terms by the denominator


(+9x^2+1-27*3*-45)=0

We get rid of parentheses

9x^2+1-45-27*3*=0

We add all the numbers together, and all the variables

9x^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{18}=0$