(1/3)(a+5)=7/2

Solution for (1/3)(a+5)=7/2 equation:

(1/3)(a+5)=7/2

We move all terms to the left:

(1/3)(a+5)-(7/2)=0


Domain of the equation: 3)(a+5)!=0

a∈R


We add all the numbers together, and all the variables

(+1/3)(a+5)-(+7/2)=0

We get rid of parentheses

(+1/3)(a+5)-7/2=0

We multiply parentheses ..

(+a^2+1/3*5)-7/2=0

We calculate fractions


((+a^2+1*2)/()+()/()=0


We calculate terms in parentheses: +((+a^2+1*2)/()+()/(), so:

(+a^2+1*2)/()+()/(

We add all the numbers together, and all the variables

(+a^2+1*2)/()+1

We multiply all the terms by the denominator


(+a^2+1*2)+1*()

We add all the numbers together, and all the variables

(+a^2+1*2)

We get rid of parentheses

a^2+1*2

We add all the numbers together, and all the variables

a^2+2

Back to the equation:

+(a^2+2)


We get rid of parentheses

a^2+2=0

a = 1; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·1·2
Δ = -8
Delta is less than zero, so there is no solution for the equation