(1/3)(c-2)=(7/3)

Solution for (1/3)(c-2)=(7/3) equation:

(1/3)(c-2)=(7/3)

We move all terms to the left:

(1/3)(c-2)-((7/3))=0


Domain of the equation: 3)(c-2)!=0

c∈R


We add all the numbers together, and all the variables

(+1/3)(c-2)-((+7/3))=0

We multiply parentheses ..

(+c^2+1/3*-2)-((+7/3))=0

We calculate fractions


c^2/()+()/()=0

We add all the numbers together, and all the variables

c^2/()+1=0

We multiply all the terms by the denominator


c^2+1*()=0

We add all the numbers together, and all the variables

c^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{0}{2}=0$