(1/3)(x-4)=(1/5)(x+2)

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Solution for (1/3)(x-4)=(1/5)(x+2) equation: 



(1/3)(x-4)=(1/5)(x+2)

We move all terms to the left:

(1/3)(x-4)-((1/5)(x+2))=0



Domain of the equation: 3)(x-4)!=0

x∈R





Domain of the equation: 5)(x+2))!=0

x∈R



We add all the numbers together, and all the variables

(+1/3)(x-4)-((+1/5)(x+2))=0

We multiply parentheses ..

(+x^2+1/3*-4)-((+1/5)(x+2))=0

We calculate fractions


((+x^2+1*5)(x+2)))/(-4)*5)(x+2))+3*)+()/(-4)*5)(x+2))+3*)=0

We calculate fractions


(((+x^2+1*5)(x+2)))*(-4)*5)(x+2))+3*))/((*(-4)*5)x)+(-4)*5)(x+2))+3*)+()*()/((*(-4)*5)x)=0

We can not solve this equation

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